C++ program to find the Armstrong number between the given range (logic explained step by step)

C++ program to find the Armstrong number between the given range

This is a program that finds the Armstrong number between the given range input from  user.

Enter first number of range:

Enter second number of range:

Armstrong numbers are like 371=3^3+7^3+1^3

Steps

User side:

1: User asked to enter starting number of interval

2: User asked to enter last number of interval

3: User displayed Armstrong number between that interval .

Developer side

1: Declare variables that are going to be used in program.

2: Input starting number of interval from user (input in an int variable)

3: Input last number of interval from user (input in an int variable)

3: Start a loop from first number to last number.

4: In the loop initialize a variable 'o' to zero and initialize a variable 'n' with the counter of the loop 'i' .

5: Start another while loop until the variable n is greater than zero.

6: In the inner loop place the following statements m=n%10;

                                         o=o+m*m*m;

                                         n=n/10;

7: Inner loop ends here.
8: Check if the counter is equal to the variable 'o'
9: If condition is true display the counter (these are the Armstrong numbers).
10: increase the counter.
11: Program ends here.

Code:

#include <iostream>

using namespace std;

void main()

{        //variable declaration

         int n, m, o, firstnumber, secondnumber, i;

         //heading

         cout<<"\t\t\tArmstrong numbers"<<endl;

         //entring of range

         cout << "Enter starting number of interval = ";

         cin >> firstnumber;

         cout << "Enter last number of interval. = ";

         cin >> secondnumber;

         cout<<"The following numbers:"<<endl;

         i=firstnumber;

         while( i<=secondnumber)

                {

                           o=0;

                           n=i;

                           while(n>0)

                                  {

                                         m=n%10;

                                         o=o+m*m*m;

                                         n=n/10;

                                  }

                           if(o==i)

                                  {

                                         cout << i << endl;

                                  }

                           i++;

                }

       cout << "are armstrong numbers between "<<firstnumber<<" and "<< secondnumber<< endl;

       system("pause");

}

Output: