C++ program to find natural log of 2 by solving a term step by step guide (logic explained) 

C++ program to find natural log of 2 by solving a term

This is a C++ program to find natural log of 2 by solving following term :

1/1 - 1/2 + 1/3 - 1/4 + 1/5. .. 

Steps

User side:

1: User asked to enter the numbers of terms.

2: User displayed with the natural log.

Developer side

1: Declare variables that are going to be used in program.

2: Input the numbers of terms from user and store it in a variable 'n'.

3: Initialize the variable 'm' with -1.

4: Start a while loop from one to numbers of terms entered by user.

5: In the loop assign 'm' with m*-1.

6: Store log in the variable 'log' using following statement  log=log+(m/i); and increase the counter by 1. While loop ends here.

7: Display the log outside the loop .

8: Program ends here.

Code:

#include<iostream>

using namespace std;

int main()

{      //Variable declaration

       int i=1;

       float n,m,log=0;

       //heading

       cout<<"\t\"This program is to find natural log of 2\""<<endl;

       //input of number of terms

       cout<<"Enter the number of terms"<<endl;

       cin>>n;

       m=-1;

       //while loop to solve the series

       while(i<=n)

       { m=m*-1;

       log=log+(m/i);

       i++;

       }

       //output of result

       cout<<"The natural log of 2 is equal to  "<<endl<<log<<endl;

       system("pause");

       return 0;

}

Output: