C++ program to find odd numbers within a range then calculate sum of evens and sum of square of odds. (logic explained)

Here is the C++ code to find odd numbers within a range then calculate sum of evens and sum of square of odds.  You all should have in mind how it works exactly. Here is the algorithm.

  Steps

User side

1: User asked to enter first number of range

2: User asked to enter second number of range that should be greater than first

3: User displayed odd numbers within range

4: User displayed sum of even numbers within range

5: User displayed sum of squares of odd numbers within range

Developer side

1: Declare variables that are going to be used in program.

2: Input first number of range

3: Input second number of range that should be greater than first

4: If second number is less than first stop program here it must be greater 

5: If second number is greater than first start a loop from first number of the range to the second 

6: In the loop check if the number is modulus of 2 if(firstNum%2==0)

7: If above condition fails show the numbers its odd

8: If the above condition true add it to a variable that is initially zero  (This is the sum of evens )

9: If the above condition false ,first multiply number by itself and then add it to a variable that is initially zero  (This is the sum of squares of odds )

10: Program ends here

Here is the C++ code.

Code:

#include<iostream>

using namespace std;

int main(){

       //declaraton of varables

       int firstNum,secondNum,sume=0,sumo=0;

              //heading

              cout<<"\n\t\t\t ***Start of program***"<<endl;

              //input of integers

              cout<<"Enter first number ";

              cin>>firstNum;

              cout<<"Enter second number (It must be greater than first number) ";

              cin>>secondNum;

              //the conditon on first & second number

              if(firstNum<secondNum)

              { cout<<"\t\t\t***First phase Odd numbers***"<<endl;

                     //loop to repeat from first to second number

              while(firstNum<=secondNum)

                           {      //to sum all evens

                                  if(firstNum%2==0)

                                         {

                                                sume=sume+firstNum;

                                         }

                                  else

                                         {      //to print odd

                                                cout<<firstNum<<endl;

                                                //to sum square of odds

                                                sumo=sumo+(firstNum*firstNum);

                                         }

                                  firstNum=firstNum+1;

                           }

                     cout<<"\t\t\t***First phase End***"<<endl;

                     cout<<"\t\t\t***Second phase sum of evens***"<<endl;

                     cout<<"Sum of Even numbers = "<<sume<<endl;

                     cout<<"\t\t\t***Second phase sum of evens***"<<endl;

                           cout<<"\t\t\***Third phase sum of square of odds***"<<endl;

                     cout<<"Sum of square ODD numbers = "<<sumo<<endl;

                     cout<<"\t\t\Third phase End"<<endl;

                    

              }

              else

                     { cout<<"First number is not less than second number"<<endl;}

              cout<<"\n\t\t\t ***End of program***"<<endl;

    system("pause");

    return 0;

}

Output: